Q.

A string of area of cross-section 4 mm2 and length 0.5 is connected with a rigid body of mass 2 kg. The body is rotated in a vertical circular path of radius 0.5 m. The body acquires a speed of 5 m/s at the bottom of the circular path. Strain produced in the string when the body is at the bottom of the circle is ..... x 10-5 . (Use Young's modulus 1011 N/m2 and g = 10 m/s2 )

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answer is 30.

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Detailed Solution

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Strain = F/AY

= mg + mv2RAY = 20 + 2520.54 × 10-6 × 1011 = 30 × 10-5

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