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Q.

A string of length 1 m and mass 2 × 10 −5 kg is under tension T. When the string vibrates, two successive harmonics are found to occur at frequencies 750 Hz and 1000 Hz. The value of tension T is _____newton.

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answer is 5.

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Detailed Solution

Successive reasonane f1=nv2l and f2=(r+1)v2l
hence f2−f1=v2l
⇒250=Tμ2l=12TmlT⇒25×104×2×10−5×1=5N

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