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Q.

A string of length 3l is connected to a fixed cylinder whose top view is shown in figure. The string is initially slack. The other end of the string (connected to a marble) is moving at a constant velocity of 10m/s as shown. The string will get stretched at some instant and impulsive tension occurs in the string. If hinge is exerting a force of 40000N for 0.25ms on the cylinder to bear up the impact of impulsive tension, then mark the correct statements. (Take string to be light, breaking tension of the string is 2×105N)
 

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a

The marble will move in a circular path of varying radius with constant speed of 53m/s, after the string is taut

b

The string will break if impulse duration is less than 0.5ms.

c

To answer above two options, the volume of θ must be given. 

d

The angle made by the velocity of marble with the length of string when it is just stretched is 600
 

answer is A, B, D.

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Detailed Solution

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The impulse exerted by the string on the cylinder is equal and opposite to the impulse exerted by  the cylinder on the string.

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|J|=4000×0.25×103=10Ns along the string.

For marble, J=0(2×10cosα)

As final velocity of marble along the string is zero

Putting J=10Ns, we get α=600.

The string wraps up around the cylinder and marble moves in a circular path of varying radius  with speed 10sinα=53m/s. The speed remains constant as only the tension force is present  which is perpendicular to the velocity of the marble.For string to break, the impulsive tension gas to be 2×105N

   40000×0.25×1032×105×Δt  t0.05  ms

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