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Q.

A string of length L is fixed at one end and carries a mass M at the other end.  The string makes 2/π revolutions per second around the vertical axis through the fixed end as shown in the figure, then tension in the string is

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a

ML

b

2 ML

c

4 ML

d

16 ML

answer is D.

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Detailed Solution

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Tsinθ=Mω2R        …(i)

Tsinθ=Mω2Lsinθ            …(ii)

From (i) and (ii)

T=Mω2L=M 4π2n2L=M 4π2(2π)2L=16 ML

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