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Q.

A string of linear mass density 0.005 kg/m is stretched by a force F=2t2N (t is in sec) as shown in figure. Given AB = 40 m. A pulse is generated at t = 0 at the end A velocity of the pulse when it reaches at B is

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a

24.5 m/s

b

20 m/s

c

32 m/s

d

40 m/s

answer is D.

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Detailed Solution

v=Fμ=dxdt

⇒2t25×10-3=20t=dxdt

on integrating, 

10t20t=x040⇒t=2sec

So when the pulse reach B the velocity will be 40m/s

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