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A student has focused the image of a candle flame on a white screen using a concave mirror. The situation is as given below,

Length of the flame = $1.5 cm .$
Focal length of the mirror = $12 cm .$
Distance of flame from the mirror = $18 cm .$
If the flame is perpendicular to the principal axis of the mirror, then distance of the image from the mirror is $-$ [[1]] $cm$ .

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Detailed Solution

If the flame is perpendicular to the principal axis of the mirror, then distance of the image from the mirror is

- 36 cm

.
Given,
height of object

h

= +

1.5 cm

.
focal length,

f

- 12 cm .

object distance,

u

= - 18 cm .

Using mirror formula,

\frac{1}{v} + \frac{1}{u} = \frac{1}{f}

Where

f

is the focal length,

u

is the object distance and

v

is the image distance.

\frac{1}{v} = \frac{1}{f} - \frac{1}{u}

\frac{1}{v} = \frac{1}{(- 12)} - \frac{1}{(- 18)}

v = - 36 cm

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