A student has studied the decomposition of a gas AB3 at 25∘C. He obtained the following data.P(mm Hg)50100200400Relative t1/2(s)4210.5 The order of the reactions is

t1/21t1/22=a2a1n−142=10050n−12=2n−1 ⇒2n−1=21 ⇒n−1=1 ⇒n=2

A student has studied the decomposition of a gas AB3 at 25∘C. He obtained the following data.P(mm Hg)50100200400Relative t1/2(s)4210.5 The order of the reactions is

t1/21t1/22=a2a1n−142=10050n−12=2n−1 ⇒2n−1=21 ⇒n−1=1 ⇒n=2

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A student has studied the decomposition of a gas $A B_{3} at 25^{\circ} C$ . He obtained the following data.
P(mm Hg) 50 100 200 400
Relative $t_{1 / 2} (s)$ 4 2 1 0.5

The order of the reactions is

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0.5

answer is B.

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$\begin{array}{l} \frac{{(t_{1 / 2})}_{1}}{{(t_{1 / 2})}_{2}} = {(\frac{a_{2}}{a_{1}})}^{n - 1} \\ \frac{4}{2} = {(\frac{100}{50})}^{n - 1} \end{array}$
$2 = 2^{n - 1} \Rightarrow 2^{n - 1} = 2^{1} \Rightarrow n - 1 = 1 \Rightarrow n = 2$

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A student has studied the decomposition of a gas AB3 at 25∘C. He obtained the following data.P(mm Hg)50100200400Relative t1/2(s)4210.5 The order of the reactions is

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A student has studied the decomposition of a gas $A B_{3} at 25^{\circ} C$ . He obtained the following data.
P(mm Hg) 50 100 200 400
Relative $t_{1 / 2} (s)$ 4 2 1 0.5

The order of the reactions is