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Q.

A student in the laboratory measures thickness of a wire using screw gauge. The readings are 1.22 mm, 1.23 mm, 1.19 mm and 1.20 mm. The percentage error is x121%. The value of x is ______________.

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answer is 150.

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Detailed Solution

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d=1.22mm+1.23mm+1.19mm+1.20mm4d=1.21mmΔd=0.01+0.02+0.02+0.014=0.064=0.015 Percentage error =0.0151.21×100=150121%x=150

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