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A student is asked to connected four cells of EMF of 1.5 V and internal resistance 0.25 ohm in series with an external resistance of 1 ohm but one cell is wrongly connected by him with its terminal reversed. Current in the circuit is

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1.2 A

0.5 A

1 A

1.5 A

answer is C.

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Detailed Solution

$i = \frac{(N - 2 m) E}{R + Nr}; i = \frac{(4 - 2 \times 1) \times 1 .5}{1 + 4 \times 0 .25}; i = 1 .5 A$

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