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Q.

A student is interested in coating a metal surface of 675 $c m^{2}$ area with 0.004 mm thickness with silver by passing a current of 96.5 amp with 50% current efficiency through a silver nitrate aqueous solution. If the time required to complete the coating is ‘x’ seconds then calculate the value of $\frac{x}{10}$ .
(Given: Density of Ag is $10 g / c m^{3},$ atomic mass of Ag=108)

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answer is 5.

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Detailed Solution

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Amount of Ag deposited $= (675 \times 0.0004) \times 10 g r a m$
$\frac{w}{E} = \frac{i \times t}{96500}$
$\frac{(675 \times 0.0004) \times 10}{108} = \frac{96.5 \times t}{2 \times 96500} [E q . w t o f A g = 108]$
   $t = 50 \sec$
   $\Rightarrow \frac{x}{10}$
   $\Rightarrow \frac{50}{10} = 5$

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