Q.

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of -0.004 cm, the correct diameter of the ball is :-

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a

0.529 cm

b

0.521 cm 

c

0.525 cm

d

0.053 cm

answer is D.

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Detailed Solution

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Reading of screw gauge

=MSR + CSR × LC + zero error

=0.5 cm +25 × 0.001 cm + 0.004 cm

=0.529 cm

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