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A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?

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A vernier calliper where the 10 divisions in vernier scale matches with 9 divisions in main scale and main scale has 10 divisions in 1 cm

A screw gauge having 50 divisions in the circular scale and pitch as 1 mm

A screw gauge having 100 divisions in the circular scale and pitch as 1 mm

A meter scale

answer is B.

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Detailed Solution

If student measure 3.50 cm, it means that there in an uncertainly of order 0.01 cm. For vernier scale with
1 MSD = 1mm and 9 MSD = 10 VSD
$∴$ LC of VC = 1 MSD - 1 VSD
$= \frac{1}{10} (1 - \frac{9}{10}) = \frac{1}{100} cm$

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