Q.

A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90s, 91s, 95s and 92s. If the minimum division in the measuring clock is 1s, then the reported mean time should be 

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a

92±2s

b

92±5.0s

c

92±3s

d

92±1.8s

answer is B.

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Detailed Solution

detailed_solution_thumbnail

T=90+91+95+9243684=92

ΔT=9290+9291+9592+9290

=2+1+3+0=6

ΔTavg=64=1.52T±ΔT=92±2S

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