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Q.

A student measures the time period of 20 oscillation of simple pendulum five times. That data set is 53 s, 52 s, 55 s, 54 s  and  51 s. If the minimum division in the measuring clock is  1 s. then the reported time period should be

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a

50±1 sec

b

52±2 sec

c

53±2 sec

d

53±1 sec

answer is D.

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Detailed Solution

tmean=ttrue=53+52+55+54+515=53sec

Mean error 0+1+2+1+25=65=1.2

Least count is 1 sec, means round off 1.2 to 1 sec.

∴ t=53±1sec

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