A student on adding (i) Na metal (ii) ${Na}_{2} {CO}_{3}$ and (iii) ${NaHCO}_{3}$ solution in acetic acid in test tubes A,B, C would observe that the gas evolved in the three test tubes respectively are

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$H_{2}, {CO}_{2}, {CO}_{2}$

${CO}_{2}, {CO}_{2} {,H}_{2}$

${CO}_{2}, CO, H_{2}$

${CO}_{2}, H_{2}, {CO}_{2}$

answer is A.

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Detailed Solution

$2 {CH}_{3} COOH + 2Na \to 2 {CH}_{3} COONa + H_{2} ↑$

$2 {CH}_{3} COOH + {Na}_{2} {CO}_{3} \to 2 {CH}_{3} COONa + H_{2} O + {CO}_{2} ↑$

${CH}_{3} COOH + {NaHCO}_{3} \to {CH}_{3} COONa + H_{2} + {CO}_{2} ↑$

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