A student performed an experiment to determine the ratio of $H_{2} O$ to ${CuSO}_{4}$ in a sample of hydrated copper(II) sulphate by heating it to drive off the water and weighing the solid before and after heating. The formula obtained experimentally was ${CuSO}_{4}$ . $5.5 H_{2} O$ but the accepted formula is ${CuSO}_{4}$ . $5 H_{2} O$ Which error best accounts for the difference in results?

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The student used a balance that gave weights that were consistently too high by 0.10g

The student weighed out too much sample initially.

The hydrated sample was not heated long enough to drive off all the water.

During heating some of the hydrated copper(II) sulphate was lost.

answer is A.

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Detailed Solution

During heating, some of the hydrated copper(II) sulphate was lost. When heated, hydrated copper sulphate loses its five crystallizing water molecules, turning from a blue substance to an anhydrous, colourless substance.

Hence the correct option is A

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