A student required 40% of marks to pass in an examination. But he scored only 110 marks and failed by 10 marks. Find the maximum marks.

let total marks = x

Pass percentage = 40% of x

He scored 110 marks and failed by 10 marks

pass percent=110+10 marks

40% of x=110 + 10 

x=$120\times \raisebox{1ex}{$100$}\!\left/ \!\raisebox{-1ex}{$40$}\right.$

Maximum marks $x=100\times 3=300$