AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A student starts with a velocity $40 km / hr$ for school at 4 km away from his house. Due to closing of school he returns soon to his house with a velocity of $60 km / hr$ . His average velocity will be__km/hr?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

Zero

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

His average velocity will be Zero.
Total Distance by the student is

4 + 4 = 8 km

, as he started his journey from his house to school and back to his house from school. Velocity at the starting of journey

= 40 km

And velocity of the student when he returns back from his school

= 60 km / h .

Average speed = \frac{Total displacement during journey}{Total time taken to cover}

Displacement is the shortest distance travelled by the body from initial point to the final point. As the student starts his journey from the same point and ends his journey at the same point.
Therefore, his total displacement will be Zero.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!