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Q.

A student wants to prepare a saturated solution of Ag+  ion. He has got only three samples  AgCl(Ksp=1.8×1010)AgBr(Ksp=5×1013)  and  Ag2CrO4(Ksp=2.4×1012). Which compound he should use to have maximum  [Ag+]:

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a

AgCl 

b

Ag2CrO4

c

Either of them

d

AgBr 

answer is C.

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Detailed Solution

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SAg+=SAgCl=KSP=1.8×1010

=1.34×105M

SAg+=SAgBr=KSP=5.0×1013

=7.07×107M

SAg2CrO4=KSP43=2.4×10-1243

=0.8×104M

Also  SAg+=2×SAg2CrO4

=0.8×104×2=1.6×104M

This will give maximum value.

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