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Q.

A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for 30 days is as follows:
0.03     0.08     0.08     0.09     0.04     0.17
0.16     0.05     0.02     0.06     0.18     0.20
0.11     0.08     0.12     0.13     0.22     0.07
0.08     0.01     0.10     0.06     0.09     0.18
0.11     0.07     0.05     0.07     0.01     0.04

you were asked to prepare a frequency distribution table, regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days. Using this table, find the probability of the concentration of sulphur dioxide in the interval 0.12 - 0.16 on any of these days.

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Detailed Solution

Let Abe the event of the concentration of Sulphur Dioxide in the interval 0.12−0.16.

Total number of days n(S)=30.
Concentration of Sulphur Dioxide in the interval 0.12−0.16 n(A)=2.
Thus, the required probability p(A)=n(A)n(S)=230=115.

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