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Q.

A stunt man weighing 80 kg drops himself gently into an open car weighing 720 kg and moving with a velocity of 80kmph. Velocity of the car after the event is

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a

36 kmph

b

72 kmph

c

80 kmph

d

78 kmph

answer is B.

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Detailed Solution

$m_{1} = 80 {kg, v}_{1} = 0$

$m_{2} = 720 kg, v_{2} = 80 kmph$

$M = 800, v = ?$

$MV = m_{1} v_{1} + m_{2} v_{2}$

$800 v = 80 (0) + 720 (80)$

$800 v = 720 \times 80$

$v = \frac{720 \times 80}{800} = 72 kmph$

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