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Q.

A stunt man weighing 80 kg drops himself gently into an open car weighing 720 kg and moving with a velocity of 80kmph. Velocity of the car after the event is 

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a

36 kmph

b

72 kmph

c

80 kmph

d

78 kmph

answer is B.

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Detailed Solution

m1 =80kg, v1 =0

m2 =720kg,  v2 =80 kmph

M=800,v=?

MV=m1v1 +m2v2

800v=80(0)+720(80)

800v=720×80

v=720×80800=72kmph

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