A submarine sends out ultrasound that returns from the seabed and is detected after 4.52. s. If the speed of ultrasound through seawater is 1470 m/s, what is the distance of the seabed from the submarine?

Given, 

The time between transmission and detection, t = 4.52 s.

Speed of ultrasound in seawater, v = 1470 m/s 

Distance traveled by the ultrasound = 2 × depth of the sea = 2d, where d is the depth of the sea. 

We know, 

Distance = Speed × Time

2d = speed of sound × time 

⇒ 2d= 1470 m/s × 4.52 s 

⇒ 2d = 6644.4 m 

⇒ d = 3322.2 m. 

Thus, the distance of the seabed from the ship is 3322 m or 3.32 km.