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A substance ‘A’ decomposes in solution following first order kinetics. Flask I contains 1 L of a 1M solution of A and flask II contains 100 ml of a 0.6 M solution. After 8 hours the concentration of A in flask has become 0.25. what will be the time taken for concentration of A in flask II to become 0.3M?

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2.4h

4.0h

0.4h

can’t be calculated since rate constant is not given

answer is B.

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Detailed Solution

The concentration of A remains ¼ th in 8 hours. Therefore $1 / {(2)}^{n}, n = 2$ and $E_{1/2} {is 8 = n × t}_{1/2} {; t}_{1/2} = 4;$ In 4 hours 0.6 will become 0.3 .

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