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A substance absorbs electromagnetic radiations of wavelength $12.3 nm &$ then emit another electromagnetic radiations of wavelength $24.6 nm$ . If ratio of number of photons absorbed to number of photons emitted is $2 : 1$ then ratio of energy absorbed to energy emitted will be

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$1 : 4$

$2 : 1$

$1 : 1$

$4 : 1$

answer is C.

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Detailed Solution

$\frac{E_{absorbed} = n_{ab} \times \frac{1240}{12.3}}{E_{emitted} = n_{em} \times \frac{1240}{24.6}} = \frac{2}{1} \times \frac{24.6}{12.3} = \frac{49.2}{12.3} = 4 : 1$

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