Q.

A substance has normal boiling point of 400 K If ΔSvap at 1 atm and 400 K is 100 JI K mole, then calculate |ΔS|surrounding  at 1 atm and 200 K for the vaporization process. 

Cp of substance in liquid phase= 50 J/mole K 

Cp of substance in vapour phase = 40 J/mole K

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answer is 210.

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Detailed Solution

Vaporization enthalpy,
ΔvapH=400×100J/moleΔ200KH=400×10010×(200400)=42000

Δsys S=42000200=210Δsurr S=Δgys S=210

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