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A substance is expanded in adiabatic process from 2L to 5L against constant external pressure of 1 bar then internal energy change will be :

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3 bar-L

-3 bar-L

6 bar-L

-6 bar-L

answer is B.

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Detailed Solution

$\begin{array}{l} W = - P V \\ = - 1 \times (5 - 2) \\ = - 3 L - a t m \\ = - 3 \times 101.33 J \\ = - 303.9 J \\ = - 3.03^{-} L \end{array}$

As,

$q = 0; Δ U = w$ .

So the correct option is b.

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