A substance which is not paramagnetic is:

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${VOBr}_{2}$

${TiCl}_{3}$

$Cr {({ClO}_{4})}_{3}$

${KMnO}_{4}$

answer is B.

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Detailed Solution

When there is unpaired electrons, then compound considered as paramagnetic and when there is no unpaired electrons, then compound is diamagnetic. More is the unpaired electrons, more is the magnetic moment value.

In KMnO₄, Mn has +7 oxidation state and has no unpaired electrons.
In Cr(ClO₄)₃, Cr has +3 oxidation state and has three unpaired electrons.
In TiCl₃, Ti has +3 oxidation state and has one unpaired electrons.
In VOBr₂, V has +4 oxidation state and has one unpaired electrons.

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