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A substance, X, undergoes a first order reaction $X ⟶ Y$
with a half life of 20 minutes. If the initial concentration of X is 2.0 M, what will its concentration be after 40 minutes?

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0.25 M

0.50 M

1.0 M

1.4 M

answer is B.

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Detailed Solution

Here,

$t = \frac{1}{k} \ln (\frac{C_{o}}{C_{t}})$

Thus,

$[A]_{t} = \frac{2}{2^{2}} = 0.50 M$

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