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A suitcase is gently dropped on a conveyor belt moving at 3 m/s. If the coefficient of friction between the belt and the suitcase is 0.5. Find the displacement of suitcase relative to conveyor belt before the slipping between the two is stopped (g = 10 m/s²)

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0.9 m

1.2 m

1.8 m

2.7 m

answer is C.

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Detailed Solution

SInce the suitcase is slipping, retardation due to friction is given by:

a = $- \frac{μMg}{M}$ =−μg

v²−u²= 2as

In the frame of the conveyer v=0 and u=3m/s

⟹−3² = −2μgs

⟹s = 0.9m

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