Questions

A suitcase is gently dropped on a conveyor belt moving at 3 m/s. If the coefficient of friction between the belt and the suitcase is 0.5. Find the displacement of suitcase relative to conveyor belt before the slipping between the two is stopped (g = 10 m/s^{2})

a

2.7 m

b

1.8 m

c

0.9 m

d

1.2 m

detailed solution

Correct option is C

SInce the suitcase is slipping, retardation due to friction is given by:

a = $-\frac{\mathrm{\mu Mg}}{\mathrm{M}}$=−μg

So

v^{2}−u^{2 }= 2as

In the frame of the conveyer v=0 and u=3m/s

⟹−3^{2} = −2μgs

⟹s = 0.9m

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