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Q.

A sum of money doubles itself in 8 years. What is the rate of interest?


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a

  12

b

  10

c

  12.5

d

  8 

answer is C.

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Detailed Solution

Concept- There is a certain amount of money which has doubled after 8 years . and now we need to find the rate of interest from which it doubled by 8 years.
By using the formula of simple interest that is
Question ImageAccording to the given question we have
Time = Question Image years
So let assume that the money is Question ImageAnd money after 8 years is Question ImageSo the difference between money after 8 years and the money at the time of investment will be our interest. That is
2x-x=
Hence, x is the interest.
Now let assume the rate of interest will be r .
By using the formula of simple interest we will get ,
SI= PRT100
P is the principal amount that is x .
R is the rate of interest which we need to find assumed as r
T is the time that is 8 years.
So let’s put the value , we will get
SI = x×100x×8=1008=252=12.5%
So , the rate of interest will be 12.5 % per annum .     Hence, the correct answer is 3) 12.5%
 
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A sum of money doubles itself in 8 years. What is the rate of interest?