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Q.

A sweet seller has 420 kaju barfis and 130 badam barfis. She wants to stack them in such a way that each stack has the same number and they take up the least area of the tray.


What is the number of barfis that can be placed in each stack for this purpose?


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a

    10

b

    23

c

    14

d

    12 

answer is A.

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Detailed Solution

Given,
Number of kaju barfis= 420.
Number of badam barfis =130.
The area of the tray occupied by the stacks of barfis will be least when she places the maximum amount of barfi’s in each stack.
Since, the stack have same number of barfis,
So, we find HCF of 420 and 130.
By using Euclid’s division algorithm, we have,
⇒420=130×3+30 ⇒130=30×4+10 ⇒30=10×3+0  
Thus, the last non-zero remainder is 10.
⇒HCF(420,130)=10  
Hence, the sweet seller should make stacks of 10 for both kinds of barfis.
Therefore, option (1)     is correct answer.
 
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