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A swimmer is capable of swimming $1.8 m s^{- 1}$ in still water. If she swims directly across a $200 m$ wide river whose current is $0.9 m s^{- 1},$ how long will it take her to reach the other side?

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$1.85 \min$

$20 \min$

$4 \min$

$4.8 \min$

answer is A.

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Detailed Solution

$t = \frac{d}{V_{b}} = \frac{200}{1.8} = 111.1 \sec$

$= 1.85 \min$

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