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A swimmer is capable of swimming $1.65 {ms}^{- 1}$ instill water. If she swims directly across a 180 m wide river whose current is $0.85 m/s$ how far downstream (from a point opposite her starting point) will she reach

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48 m

40 m

20 m

92.7 m

answer is A.

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Detailed Solution

$v_{sr} = 1.65 m/s$

$w = 180 m$

$v_{r} = 0.85 m/s$

$x = v_{r} t$

$= 0.85 \times \frac{180}{1.65}$

$x = 92.7 m$

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