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A syringe is filled with water. Its volume is 20 $c m^{3}$ and cross–section of its interior part is 4 $c m^{2} .$ The syringe is held vertically such that its nozzle is at its top and its 100g piston is pressed by eternal agent and moves it with a constant speed. The ejected water has a initial upward velocity of 2 m/s and cross–section of the beam of water at the nozzle is $1 m m^{2} .$

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The speed with which the piston is moving is 5 mm/sec.

The total work done by external agent in emptying the syringe is 0.095 J.

The external force remains constant during the process.

The external force acting on the piston is 42 N.

answer is A, C.

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Detailed Solution

$A_{1} v_{1} = A_{2} v_{2}$

$W = (0.1) (10) (0.05) + (0.02) (10) (\frac{0.05}{2}) + \frac{1}{2} (\frac{20}{1000}) {(2)}^{2}$

$W = 0.095 .$

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