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Q.

A system absorbs 10 KJ of heat and does 4 KJ of work. The internal energy of the system

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a

decreases by 6KJ 

b

Increased by 6 KJ

c

decreased by 14 KJ

d

Increased by 14 KJ 

answer is A.

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Detailed Solution

Δ∈=q+w=−10+4=−6KT

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