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Q.

A system absorbs 10 kJ of heat at constant volume and its temperature rises from 27° C to 37°C what is $ΔE (K . J)$ of reaction

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Detailed Solution

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At constant volume heat change =internal energy change So $ΔE = Q = 10 KJ$

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A system absorbs 10 kJ of heat at constant volume and its temperature rises from 27° C to 37°C what is ΔE(K.J)of reaction