A system is provided with 50 Joules of heat and the work done on the system is 10 Joules. What is the change in internal energy of the system in Joules? 

According to the first law of Thermodynamics expression for the relation between heat, work and internal energy is

 $\Delta E=q+W$

 Given $q=50;W=10$

 Then substituting all the values we get,

 $\Delta E=50+10=60$

Hence the correct option is (A).