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Q.

A system loses 300 J of heat to the surroundings and does a work of 1200 J. Change in internal energy during the process is

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a

-900 J

b

-1500 J

c

+900 J

d

+1500 J

answer is B.

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Detailed Solution

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Heat liberated by the system= -ve;

Workdone by the system      = -ve;

Change in internal energyE = - 300 J - 1200 J = -1500 J

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