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Q.

A system rejects 1500 J of heat to its surroundings and also performs 2200 J of work on its surroundings.  What is the change in the internal energy of the system?

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a

- 3700 J  

b

+ 3700 J

c

+ 700 J  

d

- 700 J

answer is C.

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Detailed Solution

dQ=dU+dW
-1500 = dU + 2200
dU = -3700 J

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