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A system undergoes a process which absorbs 500 J of heat and undergoes an expansion against external pressure of 1 atm, during the process change in internal energy is 300 J. Then, predict the change in volume (1 L-atm=100 J)

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1 L

3 L

2 L

4 L

answer is B.

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Detailed Solution

$\begin{array}{l} ΔU = q + w = q - P_{e 0} (V_{2} - V_{1}) \\ 300 = 500 - 1 (ΔV) X 100 \\ ΔV = \frac{500 - 300}{100} = 2 L \end{array}$

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