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Q.

A tall elevator is going up with an acceleration of $a = 4 m / s^{2}$ . A 4 kg snake is climbing up the vertical wall of the elevator with an acceleration of a. A 50 g insect is riding on the back of the snake and it is moving up relative to the snake at an acceleration of a. Find the friction force between the elevator wall and the snake.

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a

$1.1 N$

b

$73.1 N$

c

$72 N$

d

$57.1 N$

answer is B.

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Detailed Solution

Assume that the snake remains straight. In reference frame of ground acceleration of snake is $8 m / s^{2} (↑)$ and that of the insect is $12 m / s^{2} (↑)$ .

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[ $f_{1} =$ friction between insect and snake]
$∴ f_{1} = (\frac{50}{1000} k g) \times 22 = 1.1 N$
For snake
$f_{2} - M_{g} - f_{1} = M (8)$
[ $f_{2} =$ friction between snake and elevator]
$f_{2} = 4 \times 18 + 1.1 = 73.1 N$

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