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A tangent galvanometer has a diameter of 15 cm and 50 turn. If the horizontal component of magnetic induction intensity is 20µT , by passing current ‘I’ the deflection is 45⁰. The value of ‘I’ is.

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4.77 mA

47.7 mA

4.77 A

47.7 A

answer is A.

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Detailed Solution

$\begin{array}{l} B_{c} = B_{H} \tan θ; \frac{μ_{0} ni}{2 r} = B_{H} \tan θ \\ \frac{4 π \times 10^{- 7} \times 50 \times i}{2 \times \frac{15}{2} \times 10^{- 2}} = 20 \times 10^{- 6}; i = 47 .7 mA \end{array}$

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