Q.

 A tangent is drawn to the parabola y2=4x at the point P whose abscissa lies in the interval [1,4] . The maximum 

 possible area of the triangle formed by the tangent at P ,  the ordinates of the point P, and the x -axis is equal to 

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a

8

b

16

c

24

d

32

answer is B.

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Detailed Solution

 Tangent at point P is ty=x+t2, where the slope of  tangent is tanθ=1/t

 Now, the required area is 

A=12(AN)(PN)=122t2(2t)=2t3=2t23/2

Question Image

 Now, t2[1,4] . Then Amax occurs  when t2=4 . 

 Therefore, Amax=16

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