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Q.

 A tangential force ‘F’ acts as the top of a thin spherical shell of mass ‘m’ and radius ‘R’. The acceleration of the shell if it rolls without slipping is (f=rolling friction)

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a

5F6m

b

3F2m

c

F6m

d

6F5m

answer is A.

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Detailed Solution

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aT=Rα

From  torque  τ=Iα

2RF=(23mR2+mR2)α

2RF=53mR2α

2F=53mRα

6F5m=Rα

∴                 aT=6F5m

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