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Q.

A tangential force of 1000N is applied on upper surface of area $2 m m^{2}$ which is 0.05 m from its fixed face. Find the shift of the upper surface with respect to its fixed face if its modulus of rigidity is $0.30 \times 10^{11} N m^{- 2}$

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a

0.433 mm

b

0.734 mm

c

0.533 mm

d

0.833 mm

answer is A.

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Detailed Solution

$η = \frac{F ℓ}{A e}$

$e = \frac{F ℓ}{η A} = \frac{1000 \times 0.05}{0.3 \times 10^{11} \times 2 \times 10^{- 6}} = 8.33 \times 10^{- 4} m = 0.833 m m$

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