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A tank with vertical walls is mounted so that its base is at a height H above the horizontal ground. The tank is filled with water to a depth 'h' . A hole is punched in the side wall of the tank at a depth ' x ' below the water surface. To have maximum range of the emerging stream, the value of x is

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$\frac{H + h}{4}$

$\frac{H + h}{2}$

$\frac{H + h}{3}$

$\frac{3 (H + h)}{4}$

answer is B.

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Detailed Solution

$R = \sqrt{2 gx} \sqrt{\frac{2 (H + (h - x))}{g}}$

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