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A tap supplies water at $25^{o} C$ . A geyser receiving the tap water gives out water at the rate of 2 liters per minute at $35^{o} C$ . The power of geyser is

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700 W

1400 W

140 W

2800 W

answer is B.

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Detailed Solution

$P = \frac{m s Δ θ}{t}$

$P = \frac{V \times ρ \times S \times ∆ θ}{t} = (\frac{V}{t}) ρ . S . Δ θ$

$P = \frac{2 \times 10^{- 3}}{60} \times 10^{3} \times 4200 \times 10 = 1400 W$

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