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A test tube floats in water, with a small coin at its bottom. The mass of the test tube is equal to the mass of the seven coins, and the external volume of the tube is $16 c m^{3}$ . It just sank when the third coin was added. Then what will be the weight of each coin?

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1 gm

2 gm

1.88 gm

1.78 gm

answer is D.

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Detailed Solution

The weight of each coin is

1.78 gm

.
Given,
External volume of tube,

v = 16 c m^{3}

Mass of

7

coins,

M_{c} =

mass of the test tube.
Let's suppose the weight of the coin is

x

gram.

7 x + 2 x = 16 gm

… (its sinks when 3rd coin is added so the weight of displaced water by

2

coins the with tube will be equal to the weight of the tube and coins)

\Rightarrow x = \frac{16}{9}

⇒

x = 1.78 gm

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