(A) The acidity of alcohols follow the order 1° > 2° > 3°
(R) The +I effect of alkyl groups (3° > 2°>1°) favor the dissociations of O – H bond

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Both ‘A’ and ‘R’ are true and ‘R’ is the correct explanation of ‘A’

‘A’ is false and ‘R’ is false

Both ‘A’ and ‘R’ are true and ‘R’ is not the correct explanation of ‘A’

‘A’ is true and ‘R’ is false

answer is C.

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Detailed Solution

Alcohols possess acidic properties due to presence of polar bond, O-H bond present in it. When there are more electron releasing groups around carbon atom (that is attached to -OH group), this will decrease the polarity in alcohols.

Hence, the acidity of alcohols follow the order 1° > 2° > 3°

When bond dissociation happens between -OH group of alcohol, then it will introduce the negative charge on O atom which is destablized when there are more electron releasing group around carbon atom. Hence, more electron releasing group decreases the dissociation tendency of -OH bond.

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