Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

(A) The acidity of alcohols follow the order 1° > 2° > 3°
(R) The +I effect of alkyl groups (3° > 2°>1°) favor the dissociations of O – H bond

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

Both ‘A’ and ‘R’ are true and ‘R’ is the correct explanation of ‘A’

b

‘A’ is false and ‘R’ is false

c

Both ‘A’ and ‘R’ are true and ‘R’ is not the correct explanation of ‘A’

d

‘A’ is true and ‘R’ is false

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

detailed_solution_thumbnail

Alcohols possess acidic properties due to presence of polar bond, O-H bond present in it. When there are more electron releasing groups around carbon atom (that is attached to -OH group), this will decrease the polarity in alcohols.

Hence, the acidity of alcohols follow the order 1° > 2° > 3°

When bond dissociation happens between -OH group of alcohol, then it will introduce the negative charge on O atom which is destablized when there are more electron releasing group around carbon atom. Hence, more electron releasing group decreases the dissociation tendency of -OH bond.

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon