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A thermo couple develops 40 $μ$ V/ Kelvin . If hot and cold junctions be at 40°C and 20°C respectively then the emf develops by a thermopile using such 150 thermo couples in series shall be

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150 mV

80 mV

144 mV

120 mV

answer is D.

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Detailed Solution

Thermo emf = $E = 40 μ V / K$

$T_{h} = 40^{o} C, T_{c} = 20^{o} C$

open circuit potential difference = $∆ V = E (T_{h} - T_{c}) = 40 \times 20 = 800 μ V = 0.8 m V$

for 150 thermo couple in series, $∆ V = 150 \times 0.8 = 120 m V$

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